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sort list based on another list java

I want to sort listA based on listB. Can airtags be tracked from an iMac desktop, with no iPhone? So basically, I have 2 ArrayLists (listA and listB). Here we will learn how to sort a list of Objects in Java. We're streaming that list, and using the sorted() method with a Comparator. rev2023.3.3.43278. Premium CPU-Optimized Droplets are now available. You can use a Bean Comparator to sort this List however you desire. If not then just replace SortedMap indexToObj by SortedMap> indexToObjList. unit tests. While we believe that this content benefits our community, we have not yet thoroughly reviewed it. The answer of riza might be useful when plotting data, since zip(*sorted(zip(X, Y), key=lambda pair: pair[0])) returns both the sorted X and Y sorted with values of X. This class has two parameters, firstName and lastName. Another solution that may work depending on your setting is not storing instances in listB but instead indices from listA. Why is this sentence from The Great Gatsby grammatical? Lets look at a quick example to sort a list of strings. The method returns a comparator that compares Comparable objects in the natural order. It would be helpful if you would provide an example of your expected input and output. If we sort the Users, and two of them have the same age, they're now sorted by the order of insertion, not their natural order, based on their names. We can sort a list in natural ordering where the list elements must implement Comparable interface. The order of the elements having the same "key" does not matter. I have a list of factories. Check out our offerings for compute, storage, networking, and managed databases. @Richard: the keys are computed once before sorting; so the complexity is actually O(N^2). Thanks for contributing an answer to Code Review Stack Exchange! Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. How to make it come last.? We first get the String values in a list. Here is a solution that increases the time complexity by 2n, but accomplishes what you want. For more information on how to set\use the key parameter as well as the sorted function in general, take a look at this. The source of these elements is usually a Collection or an Array, from which data is provided to the stream. Does this require that the values in X are unqiue? How do I generate random integers within a specific range in Java? Is it possible to rotate a window 90 degrees if it has the same length and width? Python. What happens if you have in List1, 50, 40 30 , and in List2 50 45 42? QED. Let's say we have the following code: Let's sort them by age, first. vegan) just to try it, does this inconvenience the caterers and staff? How do you get out of a corner when plotting yourself into a corner, Trying to understand how to get this basic Fourier Series. This solution is poor when it comes to storage. Sort Elements of a Linked List. I think that the title of the original question is not accurate. This solution is poor when it comes to storage. i.e., it defines how two items in the list should be compared. All of them simply return a comparator, with the passed function as the sorting key. It throws NullPointerException when comparing null. rev2023.3.3.43278. The signature of the method is: T: Comparable type of element to be compared. I want to create a new list using list1 and list2 sorted by age (descending), but I also another condition that is better explained with an example: . There are at least two good idioms for this problem. Like Tim Herold wrote, if the object references should be the same, you can just copy listB to listA, either: Or this if you don't want to change the List that listA refers to: If the references are not the same but there is some equivalence relationship between objects in listA and listB, you could sort listA using a custom Comparator that finds the object in listB and uses its index in listB as the sort key. Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. The preferred way to add something to SortedDependingList is by already knowing the index of an element and adding it by calling sortedList.addByIndex(index); If the two lists are guaranteed to contain the same elements, just in a different order, you can use List listA = new ArrayList<>(listB) and this will be O(n) time complexity. Something like this? IMO, you need to persist something else. To sort the String values in the list we use a comparator. Ultimately, you can also just use the comparing() method, which accepts a sorting key function, just like the other ones. Java Sort List Objects - Comparator Summary Collections class sort () method is used to sort a list in Java. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. How do I align things in the following tabular environment? This is an old question but some of the answers I see posted don't actually work because zip is not scriptable. If we talk about the working of this method, then the method works on ASCII values. Overview Filtering a Collection by a List is a common business logic scenario. This can be elegantly solved with guava's Ordering.explicit: The last version of Guava thas supports Java 6 is Guava 20.0: First create a map, with sortedItem.name to its first index in the list. @Jack Yes, like what I did in the last example. A example will show this. Connect and share knowledge within a single location that is structured and easy to search. Does this assume that the lists are of same size? The collect() method is used to receive elements from a stream and stored them in a collection. I used java 8 streams to sort lists and put them in ArrayDeques. I think most of the solutions above will not work if the 2 lists are of different sizes or contain different items. Streams differ from collections in several ways; most notably in that the streams are not a data structure that stores elements. In Java there are set of classes which can be useful to sort lists or arrays. In this tutorial we will sort the HashMap according to value. How can this new ban on drag possibly be considered constitutional? B:[2,1,0], And you want to load them both and then produce: This can create unstable outputs unless you include the original list indices for the lexicographic ordering to keep duplicates in their original order. How is an ETF fee calculated in a trade that ends in less than a year? Any suggestions? Competitor::getPrice). If the elements are not comparable, it throws java.lang.ClassCastException. There are others concerns with your code, without going into the sort: getCompetitors() returns directly the internal list stored by your factory object. By default, the sort () method sorts a given list into ascending order (or natural order ). . The solution below is simple and should fix those issues: Location of index in list2 is tracked using cur_loclist. Now it actually works. You are using Python 3. That's right but the solutions use completely different methods which could be used for different applications. Just encountered the same problem. Thanks for learning with the DigitalOcean Community. This comparator sorts the list of values alphabetically. I did a static include of. JavaTpoint offers college campus training on Core Java, Advance Java, .Net, Android, Hadoop, PHP, Web Technology and Python. rev2023.3.3.43278. Speed improvement on JB Nizet's answer (from the suggestion he made himself). 2023 ITCodar.com. If you have any suggestions for improvements, please let us know by clicking the report an issue button at the bottom of the tutorial. 2) Does listA and listB contain references to the same objects, or just objects that are equivalent with equals()? Key and Value can be of different types (eg - String, Integer). The best answers are voted up and rise to the top, Not the answer you're looking for? But because you also like to be able to sort history based on frequency, I would recommend a History class: Then create a HashMap to quickly fill history, and convert it into a TreeSet to sort: Java List.Add() Unsupportedoperationexception, Keyword for the Outer Class from an Anonymous Inner Class, Org.Hibernate.Hibernateexception: Access to Dialectresolutioninfo Cannot Be Null When 'Hibernate.Dialect' Not Set, Convert Timestamp in Milliseconds to String Formatted Time in Java, How to Query Xml Using Namespaces in Java with Xpath, Convenient Way to Parse Incoming Multipart/Form-Data Parameters in a Servlet, How to Convert the Date from One Format to Another Date Object in Another Format Without Using Any Deprecated Classes, Eclipse 2021-09 Code Completion Not Showing All Methods and Classes, Rotating Coordinate Plane for Data and Text in Java, Java Socket Why Server Can Not Reply Client, How to Fix the "Java.Security.Cert.Certificateexception: No Subject Alternative Names Present" Error, Remove All Occurrences of Char from String, How to Use 3Des Encryption/Decryption in Java, Creating Multiple Log Files of Different Content with Log4J, Very Confused by Java 8 Comparator Type Inference, Copy a Stream to Avoid "Stream Has Already Been Operated Upon or Closed", Overload with Different Return Type in Java, Eclipse: How to Build an Executable Jar with External Jar, Stale Element Reference: Element Is Not Attached to the Page Document, Method for Evaluating Math Expressions in Java, How to Use a Tablename Variable for a Java Prepared Statement Insert, Why am I Getting Java.Lang.Illegalstateexception "Not on Fx Application Thread" on Javafx, What Is a Question Mark "" and Colon ":" Operator Used For, How to Validate Two or More Fields in Combination, About Us | Contact Us | Privacy Policy | Free Tutorials. An in-place sort is preferred whenever possible. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. if item.getName() returns null , It will be coming first after sorting. You can setup history as a HashMap or separate class to make this easier. Whats the grammar of "For those whose stories they are"? Copyright 2011-2021 www.javatpoint.com. On the other hand, a Comparator is a class that is comparing 2 objects of the same type (it does not compare this with another object). Thanks for your answer, but I get: invalid method reference: "non-static method getAge() cannot be referenced from a static context" when I call interleaveSort. Did any DOS compatibility layers exist for any UNIX-like systems before DOS started to become outmoded? Best answer! How to handle a hobby that makes income in US. Note that you can shorten this to a one-liner if you care to: As Wenmin Mu and Jack Peng have pointed out, this assumes that the values in X are all distinct. It returns a comparator that imposes reverse of the natural ordering. Sort a List of Integers 5 1 List<Integer> numbers = Arrays.asList(6, 2, 1, 4, 9); 2 System.out.println(numbers); 3 4 numbers.sort(Comparator.naturalOrder()); 5 System.out.println(numbers);. The solution below is the most efficient in this case: Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. This gives you more direct control over how to sort the input, so you can get sorting stability by simply stating the specific key to sort by. Sorting a List of Integers with Stream.sorted () Found within the Stream interface, the sorted () method has two overloaded variations that we'll be looking into. Not the answer you're looking for? Making statements based on opinion; back them up with references or personal experience. If changes are possible, you would need to somehow listen for changes to the original list and update the indices inside the custom list. So you could simply have: What I am doing require to sort collection of factories and loop through all factories and sort collection of their competitors. Whereas, Integer values are directly sorted using Collection.sort(). In this quick tutorial, we'll learn how to find items from one list based on values from another list using Java 8 Streams. good solution! It would be preferable instead to have a method sortCompetitors(), that would sort the list, without leaking it: and remove completely the method getCompetitors(). Let's say you have a listB list that defines the order in which you want to sort listA. You weren't kidding. not if you call the sort after merging the list as suggested here. I need to sort the list of factories based on price of their items and also sort list of other items from competitors for each factory. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. In addition, the proposed solution won't work for the initial question as the lists X and Y contain different entries. Beware that Integer.compare is only available from java 7. Sorting a Java list collection using Lambda expression Since Java 8 with Lambda expressions support, we can write a comparator in a more concise way as follows: 1 Comparator<Book> descPriceComp = (Book b1, Book b2) -> (int) (b2.getPrice () - b1.getPrice ()); Sorting values of a dictionary based on a list. 1. That way, I can sort any list in the same order as the source list. Given an array of strings words [] and the sequential order of alphabets, our task is to sort the array according to the order given. If you notice the above examples, the Value objects implement the Comparator interface. Sorting values of a dictionary based on a list. If the elements of the stream are not Comparable, a java.lang.ClassCastException may be thrown upon execution. Can I tell police to wait and call a lawyer when served with a search warrant? Note that you can shorten this to a one-liner if you care to: As Wenmin Mu and Jack Peng have pointed out, this assumes that the values in X are all distinct. If their age is the same, the order of insertion to the list is what defines their position in the sorted list: When we run this, we get the following output: Here, we've made a list of User objects. A stream represents a sequence of elements and supports different kind of operations that lead to the desired result. The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup, Sorting Each Entry (code review + optimization), Sorting linked list with comparator in Java, Sorting a list of numbers, each with a character label, Invoking thread for each item in list simultaneously and returning value in Java, Sort a Python list of strings where each item is made with letters and numbers. It puts the capital letter elements first in natural order after that small letters in the natural order, if the list has both small and capital letters. If you're not used to Lambda expressions, you can create a Comparator beforehand, though, for the sake of code readability, it's advised to shorten it to a Lambda: You can also technically make an anonymous instantiation of the comparator in the sorted() call: And this anonymous call is exactly what gets shortened to the Lambda expression from the first approach. Here is Whatangs answer if you want to get both sorted lists (python3). Theoretically Correct vs Practical Notation, Bulk update symbol size units from mm to map units in rule-based symbology. I am a bit confused with FactoryPriceComparator class. Here if the data type of Value is String, then we sort the list using a comparator. If they are already numpy arrays, then it's simply. Though it might not be obvious, this is exactly equivalent to, This is correct, but I'll add the note that if you're trying to sort multiple arrays by the same array, this won't neccessarily work as expected, since the key that is being used to sort is (y,x), not just y. See more examples here. In our case, we're using the getAge() method as the sorting key. Originally posted by David O'Meara: Then when you initialise your Comparator, pass in the list used for ordering. Since Comparator is a functional interface, we can use lambda expressions to write its implementation in a single line. Read our Privacy Policy. The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup. The solution assumes that all the objects in the list to sort have distinct keys. The signature of the method is: It also returns a stream sorted according to the provided comparator. I like having a list of sorted indices. What I am doing require to sort collection of factories and loop through all factories and sort collection of their competitors. Sort an array according to the order defined by another array using Sorting and Binary Search: The idea is to sort the A1 [] array and then according to A2 [] store the elements. It is defined in Stream interface which is present in java.util package. Any suggestions? Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. Linear regulator thermal information missing in datasheet. What is the shortest way of sorting X using values from Y to get the following output? NULL). To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Both of these variations are instance methods, which require an object of its class to be created before it can be used: public final Stream<T> sorted() {} Once, we have sorted the list, we build the HashMap based on this sorted list. This is generally not a good idea: it means a client of Factory can modify its internal structure, which defeats the OOP principle. This will sort all factories according to their price. Did this satellite streak past the Hubble Space Telescope so close that it was out of focus? Its likely the second set is a subset of the first. As you can see from the output, the linked list elements are sorted in ascending order by the sort method. My solution: The time complexity is O(N * Log(N)). It's a List, and Item has a public String getWeekday() method. Note: the key=operator.itemgetter(1) solves the duplicate issue, zip is not subscriptable you must actually use, If there is more than one matching it gets the first, This does not solve the OPs question. Using Kolmogorov complexity to measure difficulty of problems? Is the God of a monotheism necessarily omnipotent? As you can see that we are using Collections.sort() method to sort the list of Strings. To learn more, see our tips on writing great answers. If you already have a dfwhy converting it to a list, process it, then convert to df again? Using this method is fairly simple, so let's take a look at a couple of examples: Here, we make a List instance through the asList() method, providing a few integers and stream() them. Styling contours by colour and by line thickness in QGIS. Then we sort the list. This trick will never fails and ensures the mapping between the items in list. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. To avoid having a very inefficient look up, you should index the items in listB and then sort listA based on it. Once sorted, we've just printed them out, each in a line: If we wanted save the results of sorting after the program was executed, we would have to collect() the data back in a Collection (a List in this example), since sorted() doesn't modify the source. If you have 2 lists of identical number of items and where every item in list 1 is related to list 2 in the same order (e.g a = 0 , b = 1, etc.) Why do academics stay as adjuncts for years rather than move around? Create a new list and add first sublist to it. How can this new ban on drag possibly be considered constitutional? There is a difference between the two: a class is Comparable when it can compare itself to another class of the same type, which is what you are doing here: one Factory is comparing itself to another object. It also doesn't care if the List R you want to sort contains Comparable elements so long as the other List L you use to sort them by is uniformly Comparable.

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sort list based on another list java

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